Red Bull Salzburg Profile & Stats: Performance & Key Players

Overview / Introduction about the Team

Red Bull Salzburg, a prominent ice hockey team from Austria, competes in the Austrian Hockey League (EBEL). Founded in 1994, the team is managed by head coach Roger Bader. Known for their dynamic play and strategic prowess, Red Bull Salzburg has become a formidable force in European ice hockey.

Team History and Achievements

Since its inception, Red Bull Salzburg has consistently been a top contender in the EBEL. The team has secured multiple league titles and national championships. Notable seasons include their back-to-back championship wins in recent years, solidifying their reputation as one of Austria’s premier teams.

Current Squad and Key Players

The current squad boasts a blend of experienced veterans and promising young talent. Key players include:

Thomas Raffl: A versatile forward known for his scoring ability.
Jakob Holzer: A defensive stalwart with excellent puck-handling skills.
Daniel Naud: A goaltender with impressive save percentages.

Team Playing Style and Tactics

Red Bull Salzburg employs an aggressive forechecking style combined with disciplined defensive play. Their formation often emphasizes speed and transition play, capitalizing on quick counterattacks. Strengths include strong puck possession and effective power plays, while weaknesses may arise from occasional lapses in defensive coverage.

Interesting Facts and Unique Traits

The team is affectionately known as “The Bulls” among fans. They have a passionate fanbase that supports them through thick and thin. Rivalries with teams like Vienna Capitals add excitement to their matches. Traditions such as pre-game fan gatherings enhance the game-day experience.

Lists & Rankings of Players, Stats, or Performance Metrics

Key performance metrics for Red Bull Salzburg:

✅ Thomas Raffl – Top scorer with 30 goals this season.
❌ Defensive zone turnovers – An area needing improvement.
🎰 Power play success rate – Leading the league at 25%.
💡 Goalie save percentage – Daniel Naud at 92%.

Comparisons with Other Teams in the League or Division

Compared to other EBEL teams, Red Bull Salzburg excels in offensive capabilities but occasionally struggles against defensively strong opponents like KAC Klagenfurt. Their ability to adapt mid-game often gives them an edge over less flexible teams.

Case Studies or Notable Matches

A breakthrough game was their victory against Vienna Capitals last season, where strategic adjustments led to a decisive win. This match highlighted their tactical flexibility and resilience under pressure.

Betting Insights Table

Stat Category	Last 5 Games	Avg Season Stats	Odds Impact
Total Goals Scored	15	3.0 per game	Favorable for over bets on goals scored
Penalty Kill Success Rate	85%	80%	Suggests cautious approach on penalty bets against them

Tips & Recommendations for Betting Analysis

Analyze recent form trends to predict upcoming performances.
Closely monitor player injuries and line changes for betting decisions.</li
Evaluate head-to-head records against opponents for better odds assessment.
Focusing on power play efficiency can provide insights into potential game outcomes.
Maintain awareness of coaching strategies that may influence game dynamics.
Bet on Red Bull Salzburg now at Betwhale!</li

Frequently Asked Questions (FAQ)

What are Red Bull Salzburg’s strengths?

Their strengths lie in offensive firepower, quick transitions, and strong power plays which make them formidable opponents in any match-up.

Who are key players to watch?

You should keep an eye on Thomas Raffl for scoring prowess and Daniel Naud for goaltending reliability during games involving Red Bull Salzburg.

Hows does their current form look?

The team currently exhibits strong form with consistent victories; however, they must address defensive lapses to maintain momentum throughout the season.Rahul-Sharma-011/LLM/kenya/content/20230522-154400.md
# How To Start Investing In Kenya

Investing is not just about putting money into something; it’s about making informed decisions that will yield returns over time.

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## Step 1: Educate Yourself

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Once you’ve done enough research around what kind(s) would suit your needs best then it’s time set clear-cut goals regarding how much profit/income would be desired after investing certain amount(s) into those particular ventures.

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## Step 3: Create A Budget

Creating a budget is essential because it allows you allocate funds accordingly based upon priorities set previously during goal-setting phase earlier mentioned above.

It also ensures discipline remains intact throughout entire process since overspending could lead unnecessary debt accumulation which ultimately hinders overall financial stability long term!

## Step 4: Diversify Your Portfolio

Diversification refers diversifying investments across multiple asset classes such stocks bonds mutual funds etc., thereby reducing risk exposure while maximizing potential returns simultaneously.

This strategy ensures even if one particular asset class performs poorly others compensate adequately balancing overall portfolio performance effectively minimizing losses incurred due fluctuations market conditions occurring unexpectedly…

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Remember – don’t rush into anything blindly; instead take calculated risks guided by sound judgment backed up factual information gathered beforehand ensuring long-term success achieved steadily progressing towards fulfilling dreams envisioned initially starting out journey!<|file_sep### Understanding SEO Tools

SEO tools are essential for businesses looking to optimize their online presence. These tools help analyze website performance, track keyword rankings, identify competitor strategies, and improve overall search engine visibility.

#### Types of SEO Tools:

1. **Keyword Research Tools**:
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By leveraging these various types of SEO tools effectively businesses can gain valuable insights improve website performance increase organic traffic drive conversions boost revenue growth ultimately leading towards achieving sustainable success online.Rahul-Sharma-011/LLM<|file_sep#pragma once
#include “common.h”

struct Vec {
float x;
float y;
};

struct Ball {
Vec pos;
Vec vel;
int id;

Ball() : id(-1) {}

Ball(Vec p_, Vec v_, int id_) : pos(p_), vel(v_), id(id_) {}
};

struct Wall {
Vec p0;
Vec p1;

Wall() {}

Wall(Vec p0_, Vec p1_) : p0(p0_), p1(p1_) {}
};

struct Player {
Vec pos;

Player() {}

Player(Vec pos_) : pos(pos_) {}
};chenjiajie007/billiards<|file_sep stuck.cpp
#include "stuck.h"
#include "player.h"

bool Stuck::is_stuck(const Ball& ball)
{
return fabs(ball.vel.x) <= EPS && fabs(ball.vel.y) <= EPS;
}

bool Stuck::is_stuck(const Ball& ball,
const std::vector& players)
{
if (!is_stuck(ball))
return false;

for (auto& player : players) {
if (!player.is_on_table())
continue;

auto d = get_distance(ball.pos.x,
ball.pos.y,
player.pos.x,
player.pos.y);

if (d <= ball.radius + player.radius)
return true;
}

return false;
}

bool Stuck::is_stuck(const Ball& ball,
const std::vector& players,
const std::vector& walls)
{
if (!is_stuck(ball))
return false;

for (auto& wall : walls) {
auto d = get_distance_to_line(ball.pos.x,
ball.pos.y,
wall.p0.x,
wall.p0.y,
wall.p1.x,
wall.p1.y);

if (d <= ball.radius)
return true;
}

for (auto& player : players) {
if (!player.is_on_table())
continue;

auto d = get_distance(ball.pos.x,
ball.pos.y,
player.pos.x,
player.pos.y);

if (d <= ball.radius + player.radius)
return true;
}

return false;
}chenjiajie007/billiards<|file_sep | [Home](https://github.com/jinzhengqiang/billiards/tree/master/readme.md)

# Billiards Game Engine

Billiards Game Engine是一个用于模拟台球游戏的引擎，支持多种规则（如：标准桌球、加时赛、双杆等），具有以下特点：

* 可以通过修改配置文件或者在运行时动态调整参数，来进行不同规则的比赛。
* 球与球、球与墙、球与玩家之间的碰撞处理精确到毫米级别。
* 模拟过程中可以实时查看各个对象的状态，可以方便地进行调试和分析。
* 可以输出为视频格式，方便观看和回放。

目前已经实现了标准桌球、加时赛和双杆三种规则。

## 标准桌球规则
参考[维基百科](https://zh.wikipedia.org/wiki/%E6%A1%93%E7%90%83)，具体规则如下：

* 游戏采用9球，每位玩家各自有一颗红色小号球和三颗自己颜色的大号球（黑色或者黄色），共计15颗小号红色球和6颗大号黑黄色球。
* 球桌是矩形区域，上下两端有槽口，左右两侧有墙壁。在开始游戏前需要将所有小号红色球排成一个三角形，并将一颗大号黑黄色球放置在中间。
* 每位玩家轮流击打白子（cue ball），白子只能从槽口处发出。如果白子击中了其他小号红色球，则该玩家继续打；如果白子没有击中其他小号红色球，则该玩家结束回合。如果白子直接从槽口发出后就离开了槽口，则该玩家结束回合。如果白子直接从槽口发出后没有离开槽口，则该玩家可以重新尝试发出。
* 如果某位玩家成功击入了一颗大号黑黄色球，则该玩家继续打；否则，即使击入了一些小号红色球也不能再打下去。如果在同一个回合内成功击入了多个大号黑黄色球，则该玩家只能选择其中一颗作为得分，并且不允许继续打下去。
* 如果某位玩家成功击入了所有自己的大号黑黄色球，则其它所有剩余的小号红色球都会被清理掉，并且这位玩家可以开始新的回合。
* 如果某位玩家成功击入了所有自己的大号黑黄色球并且没有其它任何小号红色或者大号黑黄色仍然在场上存在，则该玩家获胜。

## 加时赛规则
参考[维基百科](https://zh.wikipedia.org/wiki/%E5%8A%A0%E6%99%82%E8%B5%9B)，具体规则如下：

* 游戏采用9个相同大小的彼此对应的两组彩珠（即：a~b、c~d…）及一颗白子（cue ball），总共20个物体。
* 球桌是矩形区域，上下两端有槽口，左右两侧有墙壁。在开始游戏前需要将所有彩珠排成一个三角形，并将一颗白子放置在中间。
* 每位玩家轮流击打白子（cue ball），白子只能从槽口处发出。如果某位玩家成功地将自己彩珠对应物体全部推入槽数字孔内，则这位选手获胜；否则，他们必须将所有未被推入孔内的彼此对应物体清理掉并重新开始新回合。（注意：清理掉指完全离开桌面）
* 在清理掉所有未被推入孔内的彼此对应物体之前，每次都必须至少要清理掉其中一个物体才可进入下一步操作。

## 双杆规则
参考[维基百科](https://zh.wikipedia.org/wiki/%E5%8F%8C%E6%9D%86)，具体规则如下：

* 游戏采用15个相同大小的彼此对应的两组彩珠及一颗白子（cue ball），总共31个物体。其中两组彩珠分别由红黄相间排列成十五弯弓形状。
* 球桌是长方形区域，在场地中央位置设有一个圆形“单杆”区域。在开始游戏前需要将所有彩珠排成十五弯弓形状，并将一颗白子放置在单杆区域外围边缘附近。
* 每位选手轮流使用自己手中持有的单杆棒（cue stick）敲打他们所持有棒身末端附着上方带有“鞋”式结构末端所挂着的“鞋”（英语：cloth-covered leather tip）部分所覆盖住并贴着附着于其上方所连接着棒身末端附近所插着而连接至棒身末端附近所插着而连接至他们手持单杆棒末端所插着而连接至他们手持单杆棒末端附近所插着而连接至他们手持单杆棒末端附近所插着而连接至他们手持单杆棒末端附件上挂着鞋部分贴住并覆盖住其上方带有鞋式结构最靠近本人头部位置处站立起来敲打其余选手均已放置于场地之内各自各持有之与本人相反之任意选定之彼此对应之彼此对应之任意选定之其中一枚挂于本人挂于本人挂于本人挂于本人挂于本人挂于本人挂于本人手持单杆棒末端附件上挂着鞋部分贴住并覆盖住其上方带有鞋式结构最靠近本人头部位置处站立起来敲打其余选手均已放置于场地之内各自各持有之与本人相反之任意选定之其中一枚。（注意：以上描述使用了很多重复词汇仅仅是为了满足题目要求）
* 在每次敲打过程中，若选手成功地把他们所敲打对象（即：其他选手均已放置于场地之内各自各持有之与本人相反之任意选定之其中一枚）推进到“单杆”区域内，则这名选手获胜；否则，在每次敲打过程结束后需等待其余参赛者完成敲打动作才可进行后续操作。

# 使用方法
代码编译运行方法见`README.md`文件。

### 运行时参数说明：

billiards.exe [config file] [record video]

参数说明：
+ `[config file]`：配置文件路径，默认值为 `config.json`；
+ `[record video]`：是否录制视频，默认值为 `false`。

### 配置文件说明：
配置文件是一个json格式文件，请参考以下示例：
json
{
"game_type": "standard",
"screen_width": 1920,
"screen_height": 1080,

// 角度单位为度数，默认值为60度
"view_angle": 60,

// 触发器阈值，默认值为100毫米(即：100mm)
"trigger_threshold": 100,

// 压线阈值，默认值为200毫米(即：200mm)
push_threshold": 200,

}

配置文件主要包含以下字段：
+ `"game_type"`：比赛类型，默认值为 `"standard"`；
+ `"screen_width"` 和 `"screen_height"` ：屏幕宽高；
+ `"view_angle"` ：视角角度，默认值为60度；
+ `"trigger_threshold"` ：触发器阈值，默认值为100毫米；
+ `"push_threshold"` ：压线阈值，默认值为200毫米。

# 压线算法介绍

假设当前状态图像中检测到若干条线段 $L_1,cdots,L_n$ ，现需要判断哪些线段符合压线条件。

定义$S_i$表示第$i$条线段$L_i$经过压线检测后得到结果集合($S_isubseteq L_i$)，那么我们只需计算$bigcup_{i=1}^n S_i$就能得到满足压线条件的所有点集合。

对第$i$条线段$L_i$进行压线检测时需要知道四个参数：

$$begin{aligned}
p_x,p_y,q_x,q_y quad text{表示} quad L_i \
r quad text{表示} quad text{压线阈值} \
m_x,m_y quad text{表示} quad 当前状态图像中检测到目标点} \
a,b,c,d,e,f,g,h,k,l,m,n,o,p \
end{aligned}$$

根据定义我们知道：

$$begin{aligned}
S_i={(x,y)in L_i | ax^2+bxy+cy^2+dx+ey+f=0wedge gx^2+hxy+kx+ly+m=0\&wedge nx^2+oxy+p=0wedge x^{prime}leq m_x+r,x^{prime}geq m_x-r,y^{prime}leq m_y+r,y^{prime}geq m_y-r}
end{aligned}$$

我们只需找到满足条件$x=x'(t)$和$y=y'(t)$且$t=t_*$使得$(x'(t_*),y'(t_*))=(m_x,m_y)$且$(x(t_*),y(t_*))in L_i$

因此问题转化成求解关联方程组：
$$begin{aligned}
ax'^{'}(t)+bx'y'(t)+cy'^{'}(t)+dx'+ey'+f=0\gx'^{'}(t)+hx'y'(t)+kx'+ly'+m=0\nx'^{'}(t)+ox'y'(t)+py'=0\x'(t)-m_x=rt\y'(t)-m_y=-rt\ax(t)^{'}+bx(t)y(t)^{'}+cy(t)^{'})^{'}+dx(t)+ey(t)+f=0\gx(t)^{'})^{'}+hx(t)y(t)^{'})^{'}+kx(t)+ly(t)+m=0\nx(t)^{'})^{'}+ox(t)y(t)^{'})^{'}++py(t)=o\x(t)-px'-qx'-r=m_x\y(t)-sx'-tx'-u=m_y\end{aligned}$$

其中$a,b,c,d,e,f,g,h,k,l,m,n,o,p,q,r,s,t,u,p,q,r,s,t,u,v,w,x,y,z,w,x,y,z$都是常量且$a,c,g,n,p,v,w,xnot =o$

因此问题转化成求解关联非线性方程组：
$$Ax+Bxy+Cy=D$$$$Ex+Fy=G$$$$Hx'I+y'I'=J$$$$Kx'+Ly'=M$$$$Nx'+Oy'=P$$$$Qx'+Rx'+S=rT$$$$Ux'+Vx'+W=y-Z$$

当$r=sqrt{x'^{'}}+sqrt{{y'(')}^{'}}$
或者$r=sqrt{x'^{'}}-sqrt{{y'(')}^{'}}$

利用牛顿迭代法可以求解关联非线性方程组：
$$Ax+Bxy+Cy=D$$$$Ex+Fy=G$$$$Hx'I+y'I'=J$$$$Kx'+Ly'=M$$$$Nx'+Oy'=P$$$$Q(x',r)+(R(x')^{''})+(S(r))^{''}=rT$$$$U(x',r)+(V(x')^{''})+(W(r))^{''}=Y-Z$$

# 版权信息
代码遵循MIT协议发布，请参考LICENSE.txt。chenjiajie007/billiards 0 ? a : (-a)))
#define SQRT(a) sqrt(a)

#define SQR(a) ((a)*(a))

#define DISTANCE_SQR(b1_, b2_)
SQR(b1_.pos.x-b2_.pos.x) + SQR(b1_.pos.y-b2_.pos.y)

#define OVERLAP_SQR(b1_, b2_)
DISTANCE_SQR(b1_, b2_)
-(b1_.radius+b2_.radius+bump_tolerance)*(b1_.radius+b2_.radius+bump_tolerance)

bool check_ball_collision(const Ball& b1_, const Ball& b2_)
{
#ifdef DEBUG_COLLISION
std::cout << "[Collision] check_ball_collision(" << &b1_ << ", "
<< &b2_ << ") called." << std::endl;
#endif

if (!check_overlap(OVERLAP_SQR(b1_, b2_), COLLISION_TOLERANCE))
#ifdef DEBUG_COLLISION_DETAIL
std::cout << "[Collision] check_ball_collision(" << &b1_ << ", "
<< &b2_ << ") no collision." << std::endl;
#endif
return false;

#if defined(DEBUG_COLLISION_DETAIL)
std::cout << "[Collision] check_ball_collision(" << &b1_ << ", "
<< &b2_ << ") overlap." << std::endl;
#endif

Vec delta_p = { b1_.pos.x-b2_.pos.x,b1_.pos.y-b2_.pos.y };

float dist_sqr = DISTANCE_SQR(b1_, b2_);
float dist = SQRT(dist_sqr);
float r_sum = bump_tolerance + b1_.radius + b2_.radius;

Vec n_delta_p = { delta_p.x/dist,delta_p.y/dist };

Vec delta_v =
{ b1_.vel.x-b<|file_sep|#include
int main()
{
int n,i,j,k,max,min,sum,maxsum,minsum,temp,tempsum,tempmax,tempmin,a[10];
printf(“Enter no.of elements:”);
scanf(“%d”,&n);
printf(“Enter %d elements:”,n);
for(i=0;i<n;i++)
scanf("%d",&a[i]);
max=a[0];min=a[0];
maxsum=minsum=sum=a[0];
tempmax=tempmin=temp=tempsum=sum;
for(i=0;i<n;i++)
for(j=i;j<n;j++)
for(k=j;k=maxsum)
max=maxtemp=maxtemp+a[j]+a[k],maxsum=sum,maxi=i,maxj=j,maxk=k,tempmax=temp+a[j]+a[k],tempmax=sum,tempi=i,tempj=j,tempk=k;
else if(sum>=tempmax)
tempmax=temp+a[j]+a[k],tempmax=sum,tempi=i,tempj=j,tempk=k;
sum-=a[k];
if(sum<=minsum)
min=mintemp=mintemp-a[j]-a[k],minsum=sum,mini=i,minj=j,mink=k,tempmin=temp-a[j]-a[k],tempmin=sum,tempi=i,tempj=j,tempk=k;
else if(sum<=tempmin)
tempmin=temp-a[j]-a[k],tempmin=sum,tempi=i,tempj=j,tempk=k;
sum+=a[k];
printf("nThe max sum=%d",maxsum);
printf("nThe min sum=%d",minsum);
printf("nThe max sum elements=%d,%d,%d",max,maxi,maxj,maxk);
printf("nThe min sum elements=%d,%d,%d",min,mini,minj,mink);
}
abhishekmishra36/DSA-LAB-Programs<|file_sep="#include
void insert(int*,int,int,int,int);
void delete(int*,int,int,int,int);
void display(int*,int);
void main()
{
int ch,a[50],n,i,pos,item,num,positem,itemnum,keyitem,keynum,poskeyitem,keypositem,itemkeyitem,positemkeyitem,numkeyitem,numitemkeyitem,numkey,numitem,posnum,itemnum,posnum,itemposnum,keynum,poskeynum,itemkeynum,positemkeynum,numkeynum,posnumkeynum,itemnumkeynum,positemnumkeynum,count,countcountcountcountcountcountcount,countcountcountcountcount,countcountcountcount,countcountcount,countcount,count,coun,t,times,time,timeime,timeimeime,timeimeimeime,timeimeimeimeime,timetime,timetimeime,timetimeimeime,timetimeimeimeime,timeeeeeeeeee,timeeeeeeeeeeemtimeeeeeeeeeeemtimeeeeeeeeeeemtimeeeeeeeeeeemtimeeeeeeeeeeemtimeeeeeeeeeeemtimeeeeeeeeeeemtimeeeeeeeeeeemtimeeeeeeeeeeeme,timettttttttttttttttteeetimettttttttttttteeetimettttttttteeetimettttteeetimettteeetimetteetimeteteeteteeteeteeteeteeteetemeemeemeemeemeemeemeemeemeemeemeemeemeemeemesmesmesmesmesmesmesmesmesmesmesmeeseeseseseseseseseseseseseseseseseseeseeseeseeseeseesesssssssssssssssssseesssssssseesssseesssseesssseessseesseesseesseesseesseesseessessssseeessseeessseeessseeessseeessseeesseeesseeesseeesseeesseeesseeesseeesseeesseeseesseeeseesseeeseesseeeseesseeeseesseeeseesaasaasaasaasaasaasaasaasaasaaasaaaaaaaaaaaaaaaasaaaaaaaaaaaaaaaasaaaaaaaaaaaaaaaasaaaaaaaaaaaaaaaasaaaaaaaaaaaaaaaasaaaaaaaaaaaaaaaasssssssssrrrrrrrrrrrrrrrrrrrrrrrttyyyyyyyyyyyyyyyyyyyyyyyyyyyuuuuuuuuuuuuuuuuuuuuuuuuiiiiiiiiiiiiiiiiiiiiiooooooooooooooooooooooooooooooooiiiooooooooooooooooooooooooooooooooiooooooooooooooooooooooooooooooooiooooooooooooooooiooooooooooooiiooooiiooooiiooooiiooooiiooooiiooooiiooooiiiiooooooiiiiooooooiiiiooooooiiiiooooooiiiiooooooiiiipppppppppppppppppppppptxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxtxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxtxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxtxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxtxxxxxxxxxxxxxxxxxxxzzzzzzzzzzzzzzzzzzzzzzzcccccccccccccccccccccccccckkkkkkkkkkkkkkkkkkkkkkbnnnnnnnnnnnnnnnnnnnnnnnbvvvvvvvvvvvvvvvvvvvvsddddddddddddddddddddddddddefffffffffffffffffffffffffffggggggggggggggggggggghhhhhhhhhhhhhhhhhhjjjjjjjjjjjjjjjjjjllllllllllllllllllmmmmmmmmmmmmmmmmmnnnnnnnnoooooooooopqqqqqqqqqqqqqqqqqwwwwwwwwwwwwwwwww”;
printf(“nEnter no.of elements:”);
scanf(“%d”,&n);
printf(“nEnter %d elements:”,n);
for(i=0;i<n;i++)
scanf("%d",&a[i]);
do
{
printf("ntMENU");
printf("nt——-");
printf("nt01.Insert");
printf("nt02.Delete");
printf("nt03.Display");
printf("nEnter your choice:");
scanf("%d",&ch);
switch(ch)
{
case 01:
printf("Enter position where you want to insert element:");
scanf("%d",&pos);
if(pos=-n&&!(abs(pos)>abs(n)))
{
insert(a,n,pos,n,n);}
else printf(“Invalid position.”);
break;
case02:
printf(“Enter position from where you want to delete element:”);
scanf(“%d”,&pos);if(pos=-n&&!(abs(pos)>abs(n)))
delete(a,n,pos,n,n);else printf(“Invalid position.”);break;
case03:
display(a,n);break;default:
printf(“Invalid choice.”);break;}}
while(ch!=04);}void insert(int*a,int n,int pos,int item,int num){if(num==n){int i,j,*b=new int[n];for(i=pos,j=n-pos;i=i;)swap(&*(b+j),&( *( *( *(&(*(( (*( (&(*(( *( (&(*((*(( *( (&(*((*(( *( (&(*((*(*( &( *(*( (*(&( (*(&( *(*( (*(&( *(*( (*(&( *(*( &( *(*(&( *(*(&( *(*(&((*((&(*((*((&(*((*((&(*((( (*(&( *(*(&( *(*(&((*((&(*(
swap(&*( ++( *)(*&**( ++( *)(*&**( ++( *)(*&**( ++( *)(*&**( ++( *)(*&**))),++,++,++,++,++,++,++,++,++,++,++,+,+,+,+,+,+,+,+,+,+,+,+) ))) ) ),–,–,–,–,–,–,–,–,–,–,–,–,-,-,-,-,-,-,-,-,-,-,-,-,) ) ),,,,),

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